Math
posted by Rory .
find the equation to the tangent to the curve y = (4x + 3)^5 at the point (0.5, 1), giving your answer in the form y = mx + c

dy/dx = 5(4x+3)^4 (4) = 20(4x+3)^4
when x = 1/2
dy/dx = 20(1)^4 = 20
1 = 20((1/2) + b
1 = 10+b
b = 11
y = 20x + 11
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