physics
posted by Anonymous .
A golfer wants to drive a ball a distance of 310 yards. If the 4‐wood launches the ball at an angle at 15° above the horizontal, and assuming that the drive is over level ground (i.e. the start and final vertical position is the same; vertical displacement is zero), what must be the initial speed of the ball to achieve the required distance (assume a perfectly straight drive).

Hmmm. The ball does not roll or bounce?
Time in air:
in the vertical, hf=hi+Vsin15*t1/2 g t^2
or 0=(VSin154.9t)t solve for t.
then horizontal distance..
310yards(39.3inches/yard)(.0254m/inch)=Vcos15*t
solve for V