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A train has a mass of 5.22 multiplied by 106 kg and is moving at 70.0 km/h. The engineer applies the brakes, which results in a net backward force of 1.87 multiplied by 106 N on the train. The brakes are held on for 37.0 s.

(a) What is the new speed of the train?

(b) How far does it travel during this period?

  • Physics -

    A train has a mass of 5.22*106kg? That is a really lightweight train. Think about that. My pickup truck weighs much more than that.

    Vf=vi+a t
    change vi 70km/h to m/s
    a= force/mass= -1.87*106N/(5.22*106)
    solve for vf

    distance: avg velocity*time= (vi+Vf)*t/2

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