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y = f(x) = 5 - x - 3x^2
Find the y-intercepts, x-intercepts, and the vertex

  • Math -

    y = -3^2 - x + 5
    y - int = 5
    x- int = -1.46 and 1.14 (using the quadratic equation of x = (-b+/- sqrt(b^2 - 4ac))/2a

    Vertex is derived from the sum of the x-intercepts divided by 2.
    -1.46 + 1.14 = -0.16

    Vertex input for x = -0.16

    Sub back into equation to find the y- input of the vertex

    y= -3(-0.16)^2 - (-o.16) +5
    y = 1.12

    Therefore the vertex is (-0.16,1.12)

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