posted by Anonymous .
A 0.38-kg particle has a speed of 2.0 m/s at point A and kinetic energy of 7.5 J at point B.
(a) What is its kinetic energy at A?
(b) What is its speed at point B?
(c) What is the total work done on the particle as it moves from A to B?
a,b) KE= 1/2 mass*v^2
c) the work done is the difference in energies at A,B