math
posted by jasmine .
how do you find all the real zeros for this function f(x)=x^3+9x^24x36

your expression factors by grouping
let
x^3 + 9x^2  4x  36 = 0
x^2(x+9)  4(x+9) = 0
(x+9)(x^24) = 0
(x+9)(x+2)(x2) = 0
x = 9, 2, 2
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