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John kicks a soccer ball 12 m/s at an angle of 40.0 degrees above the horizontal. What is the ball's maximum height? Where does the ball land?

  • physics -

    vertical velocity=12*sin40

    consider the vertical: at the top, vertical velocity is zero

    0=12sin40-9.8 t solve for t, then solve for height
    hf=12sin40*t -1/2 g t^2

    Horizontal : total time in air is 2t.

    distance=horizontal velocity*2t
    = 12 cos40 * 2t

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