Post a New Question

Chemistry (urgent)

posted by .

The gold foil Rutherford used in his scattering experiment had a thickness of approximately 4×10^−3 mm. If a single gold atom has a diameter of 2.9 x10^-8cm , how many atoms thick was Rutherford's foil?
Express your answer using one significant figure.

convert 4x10^-3mm to cm, and you get .04cm.

gold foil thickness divided by atom diameter.
.04cm/2.9x10^-8cm= 1379310 atoms

Is that correct? Also how am I suppose to put that into 1 significant figure? I've already tried 1x10^6 and that was wrong.

  • Chemistry (urgent) -

    One significant figure? What is your weigh? 200?100?

    Ok, convert 4E-3mm to cm. 4E-3mm*1cm/10mm=.4E-3cm=4E-4cm So I see an error there.

    number atoms=4E-4/2.9E-8= 1E4

  • Chemistry (urgent) -

    Thank you for your help.

  • Chemistry (urgent) -

    1*10^4

  • Chemistry (urgent) -

    Too late to help you much now, but maybe enough to help someone else. You mis-converted the thickness of the foil by moving the decimal point the wrong direction. 0.004 mm is equal to 0.0004 cm, not 0.04 cm. So your final answer is off by a factor of 100. 1x10^4, is the correct answer to one significant digit.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    How does Rutherford's model of the atom account for the back-scattering of alpha particles directed at the gold foil?
  2. Physics check

    In Rutherford's Gold Foil experiment, he bombarded gold with alpha particles and discovered the .... electron?
  3. Chem

    I don't understand how Rutherford's gold foil experiment proved that the positive charge of the atom had a very small volume in comparison to the whole atom. Could someone explain this to me please?
  4. Chemistry (URGENT)

    How many Al atoms thick is the aluminum foil if it is 0.00157cm thick. 1 Al atom = 286pm Convert pm to m 286pm = 2.86*10^-10m Convert m to cm 2.86*10^-10m = 2.9*10^-8cm Divide aluminum thickness and Al atom thickness 1.57*10^-3 / 2.9*10^-10 …
  5. Physics?

    In Rutherford's scattering experiments, alpha particles (charge = +2e) were fired at a gold foil. Consider an alpha particle, very far from the gold foil, with an initial kinetic energy of 2.0 MeV heading directly for a gold atom (charge …
  6. physics

    In Rutherford's scattering experiments, alpha particles (charge = +2e) were fired at a gold foil. Consider an alpha particle, very far from the gold foil, with an initial kinetic energy of 3.3 MeV heading directly for a gold atom (charge …
  7. Chemistry

    I keep getting the wrong answer? I know there is one similar to this on here but I keep getting the wrong answer. The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6×10^−3mm. If a single
  8. Chemistry

    Which of the following statements is not consistent with the results obtained in Rutherford’s gold foil experiment?
  9. Science

    Which of the following statements is not consistent with the results obtained in Rutherford’s gold foil experiment?
  10. Chemistry

    What specific evidence from the gold foil experiement led Rutherford to come to each of the following conclusions?

More Similar Questions

Post a New Question