the teacher instructed three students A,B,and C respectively to prepare a 50% (mass by volume) solution of sodium hydroxide (NaOH). 'A' dissolved 50 g of NaOH in 100 ml of water B dissolved 50g of NaOH in 100g of water while C dissolved 50g of NaOH in water to make 100ml of solution . which one of them has made the desired solution and why ?
C made the right solution bcos the whole solution is 100vol. so 50% of it is made up of NaOH and 50%of the remaining is distilled water.
C gets the class grade.
teacher instructed a b and c gave 50 ml of na chl
To determine which student has made the desired 50% solution of sodium hydroxide (NaOH), we need to calculate the mass by volume percentage for each solution.
Student A dissolved 50 g of NaOH in 100 ml of water.
Student B dissolved 50 g of NaOH in 100 g of water.
Student C dissolved 50 g of NaOH in water to make 100 ml of solution.
To calculate mass by volume percentage, we need to divide the mass of the solute by the volume of the solution, and then multiply by 100.
For Student A:
Solute Mass = 50 g
Solution Volume = 100 ml
Mass by Volume Percentage = (50 g / 100 ml) * 100% = 50%
For Student B:
Solute Mass = 50 g
Solution Volume = 100 g of water (which we assume to have the same density as 100 ml)
Mass by Volume Percentage = (50 g / 100 g) * 100% = 50%
For Student C:
Solute Mass = 50 g
Solution Volume = 100 ml
Mass by Volume Percentage = (50 g / 100 ml) * 100% = 50%
Therefore, all three students have made the desired 50% solution of sodium hydroxide (NaOH) because their solutions have the same mass by volume percentage.