3. Moving Costs
Moving company A charges $80 plus $55 an hour to move households across town. Moving Company B charges $75 an hour for cross-town moves. For what lengths of time is Moving Company B more expensive than Moving Company A? Write an inequality and solve for time t.
Show your work not just the final answer.
I am not inclined to show work for someone to copy.
costeach= costperhour*time + fixedcost
In one, the fixed cost is zero.
find time when both are equal (set the two cost equations equal to each other).
then, for times greater than that, Company B is costlier, and for times less than that, Company A is costlier.
Iam wanting help i do not want you to do it for me. I just needed it broken down in order to answer Thank you for your help.
A:
80 + 55 + 55 + 55 + 55
B:
75 + 75 + 75 + 75
Thank you for you answer Ms Sue.
To determine the lengths of time for which Moving Company B is more expensive than Moving Company A, we need to compare the costs of both companies and find the point at which Company B becomes more expensive.
Let's start by analyzing the charges of both companies:
Moving Company A charges a fixed fee of $80 plus an additional $55 per hour.
Moving Company B charges a flat rate of $75 per hour.
We need to find the time (t) for which the cost of Company B is greater than the cost of Company A.
For Company A, the cost can be expressed as:
Cost A = $80 + $55t
For Company B, the cost can be expressed as:
Cost B = $75t
To find the time (t) when Company B is more expensive than Company A, we need to set up an inequality and solve for t.
Cost B > Cost A
$75t > $80 + $55t
Next, we can solve this inequality step by step:
$75t - $55t > $80
$20t > $80
t > $80/$20
t > $4
Therefore, if the time (t) is greater than 4 hours, Moving Company B will be more expensive than Moving Company A. This means that for any length of time greater than 4 hours, Company B will have a higher cost than Company A.