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Solve. Please show all of your work.
Find the length and width of a rectangular lot with a perimeter of 108 meters if the length is 8 meters more than the width.

  • math -

    Perimeter is
    2L + 2W = 108
    L = W + 8

    Solve by substitution.

    2(W+8) + 2W = 108
    4W = 92
    Finish it.

  • math -

    The rest of your posts have been removed.

    Once you write up YOUR THOUGHTS, please re-post, and someone here will be happy to comment.

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    Can you please help me do it and understand it?

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