math
posted by christine .
Solve. Please show all of your work.
Find the length and width of a rectangular lot with a perimeter of 108 meters if the length is 8 meters more than the width.

Perimeter is
2L + 2W = 108
L = W + 8
Solve by substitution.
2(W+8) + 2W = 108
4W = 92
Finish it. 
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Can you please help me do it and understand it?