A steel block has a volume of 0.08 m and a density of 7,840 kg/m. What is the force of gravity acting on the block ( the weight ) in water?
the force of gravity does not change in water, it is equal to mass*g.
What changes in water is the upward bouyancy force, which against the force of gravity.
But the force of gravity is still pulling it downward. If it is floating, the NET force is zero. If it sinks, the net force is weight-bouyancy.
Wording of this problem could have been improved.
5,362.56
To calculate the weight of the steel block in water, we need to consider the buoyant force acting on the block. The buoyant force is equal to the weight of the fluid displaced by the block, which in this case is water.
To calculate the buoyant force, we first need to find the volume of water displaced by the steel block. The volume of water displaced by an object submerged in water is equal to its own volume.
Given:
Volume of steel block = 0.08 m^3
Density of water = 1000 kg/m^3 (approximately)
Using the formula:
Buoyant force = Weight of water displaced = Volume of water displaced x Density of water x Acceleration due to gravity
Step 1: Find the mass of the water displaced
Mass of water displaced = Volume of water displaced x Density of water
Mass of water displaced = 0.08 m^3 x 1000 kg/m^3 (density of water)
Mass of water displaced = 80 kg
Step 2: Calculate the buoyant force
Buoyant force = Weight of water displaced = Mass of water displaced x Acceleration due to gravity
Buoyant force = 80 kg x 9.8 m/s^2 (approximate acceleration due to gravity)
Buoyant force = 784 N
Therefore, the buoyant force acting on the steel block in water is 784 N. This is also equal to the weight of the block in water.