Precalc
posted by anna .
Okay for this question I know I am supposed to use the law of sines. But how can i tell what side is what?
In right triangle ABC, a = 120 and c = 140, and ÐC is the right angle. Solve the triangle. Round to the nearest tenth, if necessary.

angle A is opposite side a.
c/Sin90=a/SinA=b/SinB 
of course! thanks!