I need to find the vertical horizontal asypmtotes for x^2-4/x^2-9. For the answer I got x=3 and nor horizontal asymptote. Is this right?
x=3 is one of the 2 vertical asymptotes.
Hint: Recall that x^2-9=(x+3)(x-3) has two factors.
For f(x)=x^2-4/x^2-9
The horizontal asymptote takes up the value of
y=Lim f(x) as x->∞ and x->-∞.
I am sure you can figure that one out.