# math

posted by .

Use the “difference of squares” rule to factor the following expression
49-4y^2
my answer is going to be (7-2y)(7-2y)
I wasn't sure if it could of been (7-2y)(7+2y)

• math -

If you multiply the first equation (7-2y)(7-2y) it would equal 49-14y-14y+4y^2. After simplifying it would equal 49-28y+4y^2. The second option multiplies out to 49+14y-14y-4y^2. The 14y's cancel each other. That leaves 49-4y^2. Hope that helps.

• math -

Thank You So Much Sam! :)

## Similar Questions

1. ### Algebra

I have a few more questions that I either need help with or just need checking. Is the algebraic expression a polynomial?
2. ### Math (factoring)

Can someone check my answer? 5x^3 - 40 =5(x^3-8) =5(x-2)(x^2+2x+4) Also, how do you factor x^6-y^6 as a difference of cubes?
3. ### math help

can someone explain to me how i should factor this problem?
4. ### Math

Use common factoring and the difference of two squares to factor each expression... 5x^2-125
5. ### algebra

Use the “difference of squares” rule to factor the following expression: 100a^6-64b^8
6. ### algebra

use the "difference of squares" rule to factor the following expression. x^2-81
7. ### math

Use the “difference of squares” rule to factor the following expression 49-4y^2 Thanks :)
8. ### algebra

use the "difference of squares" rule to factor the following expression. 64z^4-81a^4
9. ### ALGEBRA

Can someone explain the following to me? 1.How do you factor the difference of two squares?
10. ### intermediate algebra

Use the difference of squares rule to factor the following expression....81z^2-49y^2

More Similar Questions