posted by fanny .
find the eqt. of tangent to the curve y=-x^2+2x-10.[ans:y=2x-10]
but my ans is y=-9. if im wrong could you show the calculation.
At what point along the curve is the tangent contact made?
Based upon the answer, it is where dy/dx = 2
dy/dx = -2x + 2 = 2, so x = 0 at the point of contact. That requires y = -10 at that point.
So y = 2x - 10 is the answer IF you are talking about the line tangent to the curve at x = 0.
You omitted an important part of the problem statement.
in the question it say: at the point where the curve cuts the y-axis