Evaluate the following integral:-
�çMvdv ,
with upper limit 'v' and lower limit 'u'
Makes no sense.
To evaluate the integral ∫ M dv with upper limit 'v' and lower limit 'u', we can follow these steps:
Step 1: Find the antiderivative of M with respect to v.
This step involves finding a function F(v) such that dF(v)/dv = M. The antiderivative represents the reverse process of differentiation.
Step 2: Evaluate the integral using the Fundamental Theorem of Calculus.
Once we have the antiderivative F(v), we can evaluate the integral by subtracting the value of F(v) at the lower limit from the value of F(v) at the upper limit, i.e.,
∫ M dv = F(v) evaluated from u to v = F(v) - F(u).
It's important to note that the antiderivative F(v) depends on the function M(v) being integrated. Therefore, we need to know the specific expression or form of M(v) to evaluate the integral accurately.