MATH 208
posted by Selena .
There were 18,017 AIDS deaths in 2003, or 34.5% of the 1995 AIDS deaths. Determine the number of AIDS deaths in 1995.
What formula who I use to solve this problem?

MATH 208 
bobpursley
What is 18,017/.35?

MATH 208 
drwls
Let the unknown # of AIDS deaths in 1995 be X.
18,017 = 0.345*X
X = 18,017/0.345 = 52,223
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