posted by Brea .
Use the following balanced equation.
3Sr(OH)2 + 2H3PO4 --> 6H20 + Sr3(PO4)2
How many mL of 0.10 M Sr(OH)2 are required to react with 30 mL of 0.30 M H3PO4?
moles H3PO4 = M x L = ?
Using the coefficients in the balanced equation, convert moles H3PO4 to moles Sr(OH)2.
Now M Sr(OH)2 = moles Sr(OH)2/L Sr(OH)2
You have M and moles, solve for L and convert to mL.