physics
posted by lee
If a ball is thrown upwards at 20 ft/sec, the height h after t seconds is given by h = 16t^2 + 20t. How many seconds does it take for the ball to reach its maximum height, and what is this height?

bobpursley
at max height, Velocity is zero.
v=dh/dt=32t+20=0 t= 20/32 seconds
calculate h at this time.
Respond to this Question
Similar Questions

algebra
ball is thrown upwards at 20 ft/sec, the height h after t seconds is given by h = 16t^2 + 20t. How many seconds does it take for the ball to reach its maximum height, and what is this height? 
Math( help please ! )
The height of a ball thrown vertically upward from a rooftop is modelled by h(t)=5t^2=20t=50, where h(t) is the ball's height above the gorund,in meters, at time t seconds after the throw a) determine the maximum height of the ball … 
math
A ball is thrown into the air with an upward velocity of 20 ft/s. Its height (h) in feet after t seconds is given by the function h(t) = –16t^2 + 20t + 2. How long does it take the ball to reach its maximum height? 
Math
With s(t) measured in feet and t in seconds, the equation s(t)= 16t^2 + 32t expresses the height of a ball above the ground after t seconds if it were thrown upward with a velocity of 32 ft/sec. (a) What is the maximum height of the … 
math
A ball is thrown into the air with an upword velocity of 36 ft/s. Its hight H in feet after t seconds is given by the function h=16t^2+36t+9. In how many seconds does the ball reach its maximum height? 
PreCalculus
1. A projectile is fired straight up from a height of 6 feet. Its height (h) in feet after t seconds is given by h = 6 + 192t 16t^2. Answer: h = 16t^2 + 192t + 6 h = 16( t^2 12t +36) + 6 +576 h = 16 (t6)^2 +582 The maximum height … 
Algebra 1
a ball is thrown into the air with an upward velocity of 32 ft per second. Its height h in feet after t seconds is given by the function h(t)=16t^2 +32t+6. How long does it take the ball to reach its maximum height? 
Math
Please help ! 1.)a catapult launches a boulder with an upward velocity of 122 feet per second. the height of the boulder, h, in feet after t seconds is givin by the function h(t)=16t^2+122t+10. what is the boulders maximum height … 
Algebra
The equation h = 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach its maximum height? 
Algebra
The equation h= 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground,at t seconds after the ball is thrown upward.How many seconds after the ball is thrown will it reach its maximum height?