calculus
posted by mimi
write it in the form of a+ib
(1+i)^2 (1i)^3

bobpursley
Hmmmm.
(1+i)(1i)(1+i)(1i)*(1i)
taking them as pairs...
the first two give (1^i^2) =2
so we have
2*2*(1i)
can you take it from here?
Now if you want to do it in polar, the problem is
(1.414@45)^2(1.414@45)^3=2@90*2@90*2) * (1i)=4(1i) Amazing...same answer
or
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