Essential Mathematics 2
posted by DestinyLashea .
Find the surface area of the closed rectangular box shown
6cm, 5cm, 3cm
S.A.= (LW)+2(HL)+2(HW)
I did: (5x6)+2(5x3)+2(6x3)=96 am I correct?

6cm, 5cm, 3cm
This formula for the surface area is for an open box with length L and width W:
S.A.(open)= (LW)+2(HL)+2(HW)
For a closed box, it would be:
S.A.(closed)= 2(LW+HL+HW)
You would do: 2(5x6)+2(5x3)+2(6x3)=? 
126. thanks

You're welcome!