Physics
posted by Kayla .
A uniform 22 kg door that is 2.5 m high by 0.80 m wide is hung from two hinges that are 20 cm from the top and 20 cm from the bottom. If each hinge supports half the weight of the door, find the magnitude and direction of the horizontal components of the forces exerted by the two hinges on the door. (Take the direction of forcing the door away from the hinges to be positive and the direction of forcing the door toward the hinges to be negative.)
Find the force of upper hinge.
Find the force of lower hinge.

draw the figure, with the hinges, and the center of gravity.
Write sum of moments about the hinges.
Here is the equation from the lower hinge:
.40meter*Weight2.1meter*Fupperhinge=0
That gives you Fupperhinge. Do the same for the other hing, but I bet a coke it is =  Fupperhinge.
check my math. 
2/4=.5
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