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The index of refraction of a transparent liquid
(similar to water but with a different index of refraction) is 1.39. A flashlight held under the
transparent liquid shines out of the transparent liquid in a swimming pool. This beam of light exiting the surface of the transparent liquid makes an angle of a = 39 degrees with respect
to the vertical.

At what angle (with respect to the vertical)is the flashlight being held under transparent liquid?

The flashlight is slowly turned away from the vertical direction.
At what angle will the beam no longer be visible above the surface of the pool? Answer in units of degrees.

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