# math

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Amy has \$200 less invested at 9% than she does at 6.5%. If the annual return from the two investments is the same, how much is invested at each rate?

• math -

If she invested \$X at 9%, then she invested \$(X+200) at 6.5%.

Since the return is the same, then
X*0.09 = (X+200)*0.065
X(0.09-0.065)=200*0.065
0.025X = 13
X = 13/0.025 = \$520 at 9%
X+200 = \$720 at 6.5%

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