f(x)=-0.092x^2+5.3x-51.2 graph f in [ 20,40,5]by[0, 30,5]
To graph the function f(x) = -0.092x^2 + 5.3x - 51.2 in the given range [20, 40, 5] by [0, 30, 5], we need to determine the y-coordinate (f(x)) for each x-value in the range.
1. Start by creating a table with x-values from the given range. The x-values should be incremented by the specified interval. In this case, the x-values are 20, 25, 30, 35, and 40 (in steps of 5).
2. Calculate the corresponding y-values (f(x)) by substituting the x-values into the function f(x) = -0.092x^2 + 5.3x - 51.2.
For x = 20:
f(20) = -0.092(20)^2 + 5.3(20) - 51.2
For x = 25:
f(25) = -0.092(25)^2 + 5.3(25) - 51.2
Continue this process for the remaining x-values.
3. Once you have calculated all the y-values, plot the points (x, y) on a coordinate plane.
4. Connect the plotted points with a smooth curve to graph the function. You can use a straightedge or the help of a graphing software/tool to draw the curve.
Here is an example of a graph of f(x) = -0.092x^2 + 5.3x - 51.2 in the range [20, 40, 5] by [0, 30, 5]:
```
Y
| |
| |
| * |
| * |
| * |
| * *|
| * |
| * |
| * |
| * |
_______|_______________________________________________ X
20 25 30 35 40
```
Note that this is just a rough sketch, and a graphing software/tool will provide a more accurate and precise graph of the function.