A proton is moving in a circular orbit of radius 11.8 cm in a uniform magnetic field of magnitude 0.232 T directed perpendicular to the velocity of the proton. Find the orbital speed of the proton. Answer in units of m/s.
I came up with .118/2.83x10^-7 and it was incorrect.
(2pie(1.67x10^-27)/ (1.60x10^-19)x .232= 2.83x10^-7
.118/2.83x10^-7 wrong answer. I have entered three wrong answers and can not pass this if I can not get the right answer. Please help!
bobpursley, Friday, April 15, 2011 at 11:43am
Bqv=mv^2/r
v=Bqr/m
v= .232*1.6E-19*.118/1.67E-27
Check that. Now compare it with whatever you did, I cant figure out what you did.
for information, if you posted this as your answer: .118/2.83x10^-7
I don't understand what you did, and why did you not simplify this. I get about 4.17E5 m/s from that fraction.
Check my work and see what I got from my calcs.
Calculating v gave me 2.62285030e-48
so I then divide .118/ans and get 4.4989e46 would this be right?
You are having a major problem working your calculator. Do you have the manual?
look at the powers: 1E-19/1E-27=1E8
No, your calculation is incorrect. Let me explain how to correctly calculate the orbital speed of the proton.
The equation you need to use is v = Bq / (m * r), where v is the orbital speed, B is the magnitude of the magnetic field, q is the charge of the proton, m is the mass of the proton, and r is the radius of the circular orbit.
First, let's plug in the given values: B = 0.232 T, q = 1.60 x 10^-19 C (charge of a proton), and r = 11.8 cm = 0.118 m. We also know the mass of a proton, which is m = 1.67 x 10^-27 kg.
Now, let's substitute these values into the equation:
v = (0.232 T) * (1.60 x 10^-19 C) / [(1.67 x 10^-27 kg) * (0.118 m)]
First, let's simplify the numerator:
(0.232 T) * (1.60 x 10^-19 C) = 3.712 x 10^-20 T C
Now, let's substitute the simplified values into the equation:
v = (3.712 x 10^-20 T C) / [(1.67 x 10^-27 kg) * (0.118 m)]
Now, let's simplify the denominator:
(1.67 x 10^-27 kg) * (0.118 m) = 1.9706 x 10^-28 kg m
Finally, let's substitute the simplified values into the equation:
v = (3.712 x 10^-20 T C) / (1.9706 x 10^-28 kg m)
Now, let's calculate the value of v using a calculator:
v = approximately 1.883 x 10^8 m/s
Therefore, the orbital speed of the proton is approximately 1.883 x 10^8 m/s.