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how is the speed determined of a falling object? what is the pull of gravity feet per second.

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    when an object is dropped from a certain height, it is a freefall. when in freefall, the only external force acting on the body is gravitational force (neglecting air resistance). the motion of the object is unformly accelerated motion:
    (v2)^2 - (v1)^2 = 2*g*h
    where
    v2 = final velocity
    v1 = initial velocity
    h = height or distance traveled
    g = acceleration due to gravity (9.8 m/s^2)
    solving for velocity:
    v2 = sqrt[ 2gh - (v1)^2 ]
    when the object starts from rest (and thus v1 = 0),
    v2 = sqrt(2gh)

    hope this helps~ :)

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