Math

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given the fonction: y=3x^2-5x and x=g(t)derivable as g(14)=-4 and g'(14)=2

calculate dy/dt in t = 14

  • Math -

    y = 3x^2 - 5x
    = 3(g(t)^2 - 5g(t)

    dy/dt = 6 g(t) d(g(t))/dt - 5 d(g(t))/dt
    = 6(g(14)) d(g(14))/dt - 5 d(g(14))/dt
    = 6(-4)(2) - 5(2)
    = -58

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