Physics

posted by .

(a) Find the speed of a satellite moving around the earth in a circular orbit that has a radius equal to six times the earth's radius of 6.38 x 10^6 m.

(b) Find the satellite's orbital period.

  • Physics -

    centripetalforce=gravity force

    v^2/r=9.8/(6)^2

    V= sqrt (6*re*9.8/36)

    checkthat.

    Period? Well, T=distance/velocity=2PI*6Re/above V

    That will give the period in seconds, you probably want to convert it.

  • Physics -

    (a) centrieptal acceleration rate =
    V^2/r = GM/r^2

    where M is the mass of the earth and r = 6 Re.
    Re is the radius of the earth that you were given
    G is the universal constant of gravity.

    Solve for V

    V^2/(6 Re) = GM/(6Re)^2

    You can save yourself the trouble of looking up M and G by using the relationship
    g = GM/Re^2. Then
    6 V^2 /Re = GM/Re^2 = g
    V^2 = (Re*g/6)
    V = 3230 m/s

    (b) V*(period) = 2 pi R = 12 pi Re

    Solve for the period

  • Physics -

    Vc = sqrt(µ/r) where µ = 3.9863x10^14 and r = 6378km.
    At 38,268km,
    Vc = sqrt[3.9863x10^14/6x6,378,000] =

    The period derives from
    T = 2(Pi)sqrt[r^3/µ]

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    (a) Find the speed of a satellite moving around the earth in a circular orbit that has a radius equal to six times the earth's radius of 6.38 106 m. (b) Find the satellite's orbital period.
  2. physics

    A 512 kg satellite is in a circular orbit about the Earth at a height above the Earth equal to the Earth's mean radius. (a) Find the satellite's orbital speed. (b) Find the period of its revolution. (c) Find the gravitational force …
  3. physics

    A 581 kg satellite is in a circular orbit about the Earth at a height above the Earth equal to the Earth's mean radius. the orbital speed is 5590.98 m/s. Find the period of its revolution.
  4. Physics

    (a) Find the speed of a satellite moving around the earth in a circular orbit that has a radius equal to five times the earth's radius of 6.38 106 m. (b) Find the satellite's orbital period. Please Help!
  5. physics

    Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 418 km above the earth’s surface, while that for satellite B is at a height of 731 km. Find the orbital speed for (a) satellite A …
  6. physics

    Find the speed of a satellite in a circular orbit around the earth with a radius 2.69 times the mean radius of the earth; Radius Earth= 6.37E+3km; Mass Earth= 5.98E+24kg.
  7. Physics Circular Motion

    A satellite in orbit around the earth has a period of one hour. An identical satellite is placed in an orbit having a radius that is nine times larger than that of the first satellite. What is the period of the second satellite?
  8. physics

    A satellite is in a circular orbit around the Earth at an altitude of 3.30 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of …
  9. physics

    NASA launches a satellite into orbit at a height above the surface of the Earth equal to the Earth's mean radius. The mass of the satellite is 550 kg. (Assume the Earth's mass is 5.97 1024 kg and its radius is 6.38 106 m.) (a) How …
  10. physics

    Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 427 km above the earth’s surface, while that for satellite B is at a height of 873 km. Find the orbital speed for (a) satellite A …

More Similar Questions