math
posted by ed .
my son has to draw a figure with an area of 63 and a perimeter of 32.how do he go about doing it?

what kind of figure?
circle?, square?, triangle? , rectangle?, ...... 
Area of a rectangle = length times width
The factors of 63 are:
3 * 21
9 * 7
Perimeter = 2 times length plus 2 times width
The rectangle can't be 3 by 21 since its perimeter would be 6 + 42
The dimensions must be 9 by 7.
(2 * 9) + (2 * 7) = 18 + 14 = 32
He needs to draw a rectangle that measures 9 by 7.