determine the molar concentration of Ca^2+ and Cl- in a .075 M CaCl2 solution
To determine the molar concentration of Ca^2+ and Cl^- in a CaCl2 solution, we need to understand the dissociation of CaCl2 in water.
CaCl2 dissociates into Ca^2+ and 2Cl^- ions in solution. This means that for every 1 mole of CaCl2 that dissolves, it will produce 1 mole of Ca^2+ and 2 moles of Cl^- ions.
Given that the concentration of the CaCl2 solution is 0.075 M, it means that there are 0.075 moles of CaCl2 per 1 liter of the solution.
Since the molar ratio of CaCl2 to Ca^2+ is 1:1, the concentration of Ca^2+ in the solution is also 0.075 M.
However, the molar ratio of CaCl2 to Cl^- is 1:2, which means that for every mole of CaCl2, we have 2 moles of Cl^-. Therefore, the concentration of Cl^- in the solution is twice that of CaCl2, which is 0.075 M multiplied by 2, resulting in 0.15 M.
So, the molar concentration of Ca^2+ is 0.075 M and the molar concentration of Cl^- is 0.15 M in the 0.075 M CaCl2 solution.