Post a New Question


posted by .

The drawing shows a version of the loop-the-loop trick for a small car. If the car is given an initial speed of 4.6 m/s, what is the largest value that the radius r can have if the car is to remain in contact with the circular track at all times

  • physics -

    at the top, mv^2/r=mg


  • physics -

    oops. Stinking thinking, I didn't read it.

    at the top mv^2/r=mg

    but v a the top is the initial v, minus that lost to PEnergy

    or vf= sqrt (4.6^2-2*9.8*h)

    now, to the solution
    vf^2/r= g
    (4.6^2-2*9.8*2r)^2 =rg
    solve for r

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question