pre calculus
posted by henry baliz .
let f(x)= x^2  1. evaluate f(x)at x=6, 6

f(x)=x^21
f(6)=(6)^21=361=37
f(6)=(6)^21=361=37
So we see that for this particular function, f(6)=f(6).
In fact, since f(x) is an even function (consisting of even powers of x), this property of f(x)=f(x) is true for all values of x.
You can try out other pairs, such as f(2) and f(2) to verify this property.
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