x+3=0
how do you graph that?
y= -1
how would you graph that?
nevermind i figured out y= -1 but how would you graph x+3=0
y = x + 3
Pick values for x, solve for y
Example,
x = 0
y = x + 3
y = 0 + 3
y = 3
(0, 3)
x = -1
y = x + 3
y = -1 + 3
y = 2
(-1,2)
x = 1
y = x + 3
y = 1 + 3
y = 4
(1,4)
Picks more values for x as needed. Use these points to graph.
To graph the equation x+3=0, you can follow these steps:
Step 1: Get the equation in the form of y = mx + b, where m is the slope and b is the y-intercept.
In this case, we have x + 3 = 0. To isolate x, subtract 3 from both sides of the equation:
x = -3
Therefore, the equation can be rewritten as y = 0x - 3 or simply y = -3.
Step 2: Since the equation is linear (a straight line), you only need two points to plot it on a graph.
Choose two values for x and substitute them into the equation to find the corresponding y-values.
Let's choose x = -2 and x = 1.
When x = -2: y = -3
When x = 1: y = -3
These two points are (-2, -3) and (1, -3).
Step 3: Plot the two points on a coordinate plane and draw a straight line passing through them.
The graph of the equation x+3=0 is a horizontal line passing through the point (-2, -3) and (1, -3).
Now, let's move on to the next question.
To graph the equation y = -1, you can follow these steps:
Step 1: Since the equation is already in the form y = mx + b, where m is the slope and b is the y-intercept, we can directly identify the y-intercept from the equation.
In this case, the y-intercept is -1, which means the line intersects the y-axis at the point (0, -1).
Step 2: Since the equation is a horizontal line with a constant y-value, the line will be parallel to the x-axis.
Step 3: Plot the y-intercept (0, -1). Since it is a horizontal line, it means that for any x-value we choose, the y-value will always be -1.
Therefore, the graph of the equation y = -1 is a horizontal line passing through the point (0, -1) and is parallel to the x-axis.