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I have trouble finding the solution for this: Find the equation of the line through (2,a) and (4,b).

  • math -

    slope = (b-a)/2

    using (2,a)
    y-a = (b-a)/2 (x-2)
    times 2
    2y - 2a = (b-a)(x-2)
    2y - 2a = bx - 2b - ax + 2a

    ax - bx + 2y = 4a - 2b
    (a-b)x + 2y = 4a - 2b

    check if point not used lies on it ....

    LS= (a-b)(4) + 2(b)
    = 4a - 4b + 2b
    = 4a - 2b
    = RS

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