MATH_ALGEBRA
posted by Anonymous .
The price to cover ornaments is a fixed amount plus a percentage of the value of the ornaments.
It costs $32 to insure $1000 worth of jewellery or $44.50 to insure $3500 worth of jewellery.
What is the fixed amount to insure jewellery?
A. $27.00
B. $31.25
C. $44.65
D. $58.82
This is what I got told to you, but like y do u have to subtract, I get the first equation, I don't get the second, and It still has to be solved. I really don't understand, please help
F = fixed amount
P = percentage
F + P(1000) = 32
[f + p(3500) = 44.50]

MATH_ALGEBRA 
helper
(1) F + 1000P = 32
(2) F + 3500P = 44.50
you have to solve these 2 equations simultaneously
By elimination method, to eliminate F, multiply one of the equations by 1
1(F + 1000P = 32)= F  1000P = 32
Now ADD these two equations together
F  1000P = 32
F + 3500P = 44.50
0 + 2500P = 12.5
2500P = 12.5
P = .005
substitute P = .005 in one of the equations to find F
F + 1000P = 32
F + 1000(.005) = 32
F + 5 = 32
F = 27
What is the fixed amount to insure jewellery?
A. $27 
MATH_ALGEBRA 
Anonymous
Thank you so much Helper

MATH_ALGEBRA 
helper
you're welcome :)
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