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I am looking for help integrating using u substitution over the interval of 0 to pi/2 the function cos(2x/3)

  • Math -

    the perimeter of parallelogram is 52cm,and jk is 2cm longer than jm.

    find jk
    find jm

  • Math -

    Integrate cos (2x/3) dx

    u = 2x/3
    du = 2/3 dx
    3/2 du = dx

    I = integrate symbol

    I cos (2x/3) dx = I cos u 3/2 du
    I cos (2x/3) dx = 3/2 I cos u du
    I cos (2x/3) dx = 3/2 sins u

    since, u = 2x/3
    I cos (2x/3) dx = 3/2 sin (2x/3)

  • Math -

    I cos (2x/3) dx = 3/2 sin (2x/3)

    sorry, forgot 0 to pi/2

    3/2 sin 2/3 (pi/2) - 3/2 sin 0
    3/2 sin (2pi/6) - 0
    3/2 sin (pi/3)
    3/2 (sqrt3/2)
    3 sqrt3/4

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