How much heat is required to raise the temperature of 70 g of water from 20 C to 80 C?
70 x 60 x 1 = 4200 calories
210
To calculate the heat required to raise the temperature of a substance, you can use the equation:
Q = m * c * ΔT
where:
Q is the heat energy (in Joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
For water, the specific heat capacity is approximately 4.18 J/g°C.
Now, let's calculate the heat required to raise the temperature of 70 g of water from 20°C to 80°C:
Q = 70 g * 4.18 J/g°C * (80°C - 20°C)
Q = 70 g * 4.18 J/g°C * 60°C
Q = 17676 J
Therefore, the heat required to raise the temperature of 70 g of water from 20°C to 80°C is 17676 Joules.
To calculate the amount of heat required to raise the temperature of water, you can use the formula:
Q = mcΔT
Where:
Q is the heat energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in joules per gram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
The specific heat capacity of water is approximately 4.186 J/g°C.
Given:
m = 70 g (mass of water)
ΔT = (80°C - 20°C) = 60°C (change in temperature)
c = 4.186 J/g°C (specific heat capacity of water)
Plugging these values into the formula, we can calculate the heat energy (Q):
Q = (70 g) * (4.186 J/g°C) * (60°C)
Q ≈ 17576.4 J
So, approximately 17576.4 joules of heat energy is required to raise the temperature of 70 grams of water from 20°C to 80°C.