Algebra
posted by Robert .
Michelle sold tickets for the basketball game. Each adult ticket costs 3$ and each student ticket costs 1.50. There were 105 tickets sold for a total of 250$. How many of each type of ticket were sold?

x = adult tkts
y = student tkts
3x = value of adult tkts
1.5y = value of student tkts
x + y = 105
3x + 1.5y = 250
solve these equation together
for your answer
post back if you need more help 
How do you solve the equations? ):

(1) x + y = 105
(2) 3x + 1.5y = 250
multiply equation (1) by 3
3 (x + y = 105) = 3x  3y = 315
add the two equations together
3x  3y = 315
3x + 1.5y = 250
0  1.5y =  65
1.5y = 65
y = 43.33 student tkts
x + y = 105
x + 43.33 = 105
x = 61.67 student tkts
are you sure you typed this problem right?
because there were 61.67 adult tkts
and 43.33 student tkts
the number of tkts should not be a fraction, but I checked this 4 times
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