trigonometry
posted by anon .
sinA= 3/5 and C=17
Finding a and b

sin A = 3/5 = a/c
if side a = 3 and side c = 5
you should recognize this as a
special rt triangle of 345
so b = 4
If not
a^2 + b^2 = c^2
3^2 + b^2 = 5^2
b^2 = 16
b = 4
so, a = 3, b = 4