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sinA= 3/5 and C=17
Finding a and b

  • trigonometry -

    sin A = 3/5 = a/c

    if side a = 3 and side c = 5
    you should recognize this as a
    special rt triangle of 3-4-5
    so b = 4

    If not
    a^2 + b^2 = c^2
    3^2 + b^2 = 5^2
    b^2 = 16
    b = 4

    so, a = 3, b = 4

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