PhysicsPlease check my answerI've been working o
posted by Sheila .
If I went tubing with my little sister, and I have a larger mass, why would we both reach, in terms of energy, the bottom of the hill at the same time;
Originally I thought because we would both be accerlerating at the same rate but that doesn't explain the energy part does it?
But then I think it would be because the TE(top) of the hill = TE(bottom of hill) and when you set that equation up, mass drops out, correct?

PhysicsPlease check my answerI've been working o 
bobpursley
It is rather neat the answer to this,and you need to thank your teacher for asking this neat question.
Now you know what is moving you is Graviational attraction, which depends on your mass
Fg= GMearth*Massyou/radiusearth^2
so clearly, the Earth is pulling on You much harder than sis.
But what is really neat about this, is to compare what that differing force does on you and your sister.
Newtons second law:
Force=mass*acceleration or
acceleration= Force/mass
Your acceleration= Yourgraviationalforce/your mass= GMearth/radiusearth^2
and low and behold, your sister has the same acceleration down the hill. It isn't g, it would be g if you fell vertically, but is the same.
Now in terms of energy: Consider both of you having the same potential energy at the top of the hill, say PEorig.
That PEorinal becomes kinetic energy as you go down the hill.
Because the amount of work Gravity is doing (work= force*distance) is different on each of you, lets see what it does to each of your Kinetic energies.
workyou=force*distance=GMe*Myou*distance/radiusearth^2
and
worksister=GMe*Msister*distance/radiusearth^2
but kinetic energy gained has to equal this work done.
KEyou= 1/2 massyou*v^2=GMeMyou*distance/radiuearth^2
or v^2=2(GMe*distance/rearth^2)
but if you do the same thing finding the KE of your sister, guess what (do the math), for your sister
V^2=2*GMe*distance/rearth^2)
now since you went the same distance, you have the same velocity. 
PhysicsPlease check my answerI've been working o 
Sheila
Thank you for the detailed answerI actually get it and understand itthank you again!!
Respond to this Question
Similar Questions

PhysicsPlease check
If I went tubing with my little sister, and I have a larger mass, why would we both reach, in terms of energy, the bottom of the hill at the same time; Originally I thought becuase we would both be accerlerating at the same rate but … 
physics
A 15.0 kg stone and a 150 kg stone are released from rest at the same height above the ground. There is no appreciable air drag. Which of the following statements is or are true? 
physics
You are pulling your sister on a sled to the top of a 20.0 m high, frictionless hill with a 10.0° incline. Your sister and the sled have a total mass of 50.0 kg. You pull the sled, starting from rest, with a constant force of 127 … 
8th grade physical science
You are on roller blades on top of a small hill. Your PE is 1,000.0 Joules. The last time you check your mass was 60.0 kg. What is the height of the hill? 
Physics
You are at the park. You are going to analyze a roller coaster. You ask the attendant for the height of the first hill and find out that it is 106.1 feet tall. Along with your group members, you pace off a train waiting to be loaded. … 
Physics
Could someone please explain how you get this answer? 
PHYSICS
Hi! I have some questions from a study guide in my physics class, and they give me the answer, but I have to show how to get the answer. I did most of them, but need help with this. All I need is a formula, please. :)Thank you! Here … 
physics
A 5.00kg stone and a 50.0kg stone are released from rest at the same height above the ground. There is no appreciable air drag. Which of the following statements is or are true? 
Physics
A toboggan, with rider, has a combined mass of 60kg at the top of a 5.0m hill. They are given an initial push of 2.0m/s. The distance down the hill was 20m. The velocity at the bottom of the hill is 10m/s. If the actual speed at the … 
Science halp
6.Two cars with different masses travel at the same speed down a hill toward a stop sign. What will happen when both cars apply brakes at the same time to stop?