physics
posted by michelle .
Two charges are placed on the x axis. One of the charges (q1 = +9.4 µC) is at x1 = +3.1 cm and the other (q2 = 22 µC) is at x2 = +9.3 cm.
Find the net electric field (magnitude and direction) at x = +6.5 cm. (Use the sign of your answer to indicate the direction along the xaxis.)
I changed the radius by 6.503.1 and then 6.59.3 and but then in the equation and then added but im not getting the right answer.

Both E are in the direction to the right. So they add.
Etotal= kqleft/(.065.031)^2 + kqright/(.094065)^2
You can me fancy to let the sign do the direction, as in here...
E=kq1 *(.065.031)/ABS(.065.031)^3 + kq2(.065.093)/ABS(.065.093)^3
That again, will yield a E that is +,to the right.