Chemistry (acids and bases)

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Calculate pH, pOH, [H+], [OH-], and Ka for a 0.026 M solution of HI (a strong acid). Please help me :(

  • Chemistry (acids and bases) -

    strong acid; then it is completely dissociated.

    [H]=.026
    pH= -log (.026)=1.58
    pOH= 14-pH= you do it.
    [OH]=1E-14/.026=3.85E-13

  • Chemistry (acids and bases) -

    thank you! :D

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