Chemistry

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The solubility of Ag2S is 2.48x10^-15 mol/dm3. Calculate its solubility product.

• Chemistry -

Write the equation:

Ag2S<<>>2Ag+ + S-- when in equilibrium

ksp= [Ag+]^2 [S--]/[Ag2S]

ksp= (2x)^2 (x)/x

you are given x as 2.48E-15

solve for ksp
=4x^2

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