Chemistry
posted by Suha .
The solubility of Ag2S is 2.48x10^15 mol/dm3. Calculate its solubility product.

Write the equation:
Ag2S<<>>2Ag+ + S when in equilibrium
ksp= [Ag+]^2 [S]/[Ag2S]
ksp= (2x)^2 (x)/x
you are given x as 2.48E15
solve for ksp
=4x^2
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