Physics
posted by George .
A catapult throws a projectile at a 40.0° angle with a velocity of 26.0 m/s. How high will the projectile reach, and how far away will the projectile land?

u =horizontal speed = 26 cos 40 = 19.9 m/s
Vi initial vertical = 26 sin 40 = 16.7 m/s
time to top:
v = 0 = Vi  9.8 t
9.8 t = 16.7
t = 1.705 s to top (3.41 s total in air)
HOW HIGH?
h = 0 + Vi t 4.9 t^2
= 16.7(1.705)  4.9 (1.705)^2
= 28.47  14.25
= 14.2 meters
HOW FAR?
u * time in air = 19.9*3.41 = 67.9 m 
A superhero is leaping from the roof of one building onto another. The first building is 120 meters high and the second building is 80 meters high. The horizontal velocity of the superhero is 12.0 m/s. What is the maximum possible distance between buildings that the hero can leap across?
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