Logarithm law question

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Hello, i was wondering if e^(2t) is equivalent to e^(t^2). I cant seem to find if this is true or not.
Thanks

• Logarithm law question -

e^(2t) is equal to e^(t^2) if and only if t=2 or t=0, simply because 2t=t² for these two values of t.

Since in general, 2t≠t², e^(2t) is not equivalent to e^(t^2).

For example, t=4,
e2t=e8=2980.96
e=e16=8886110.52

The confusion arises probably because
e2t=(et
while
e=(e^t)^t

Hope that clears it up.

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