Logarithm law question

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Hello, i was wondering if e^(2t) is equivalent to e^(t^2). I cant seem to find if this is true or not.
Thanks

  • Logarithm law question -

    e^(2t) is equal to e^(t^2) if and only if t=2 or t=0, simply because 2t=t² for these two values of t.

    Since in general, 2t≠t², e^(2t) is not equivalent to e^(t^2).

    For example, t=4,
    e2t=e8=2980.96
    e=e16=8886110.52

    The confusion arises probably because
    e2t=(et
    while
    e=(e^t)^t


    Hope that clears it up.

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