If the length of a rectangle is x - 5 and the area is 4x(exponent2) - 12x +9, what is the width?
To find the width of the rectangle, we need to solve the equation. The area formula for a rectangle is given by length times width. So, we can set up the equation:
Area = Length * Width
The length of the rectangle is given as x - 5. So, the equation becomes:
4x^2 - 12x + 9 = (x - 5) * Width
To solve for the width, we need to isolate the variable "Width" on one side of the equation. Let's start by expanding the right side of the equation:
4x^2 - 12x + 9 = x * Width - 5 * Width
Next, we can rearrange the equation to isolate the terms with "Width" on one side:
4x^2 - x * Width - 12x + 5 * Width = 9
Now, we can combine like terms:
4x^2 - (x * Width) - 12x + (5 * Width) = 9
To determine the width, we need to factor the equation or use another method to find the values of x and Width that satisfy the equation. Unfortunately, without additional information or constraints, we cannot determine a specific value for the width of the rectangle.