college physics
posted by jessica .
One cm of a 10cmlong rod is made of metal, and the rest is wood. The metal has a density of 5000kg/m^3 and the wood has a density of 500kg/m^3. When the rod is set into pure water, the metal part points downward. How much of the rod is underwater?

college physics 
bobpursley
well, you know the metal will all be underwater. So the question is how much wood is under to support the weight of the metal.
bouyancy of wood= h*density water*area*g
that has to equal the weight of the entire rod.
h*densitywater(area)g.1*densitymetal*g(area h*denstiywood*area*g=0
dividing out area, g; divideing by density water.
h.1spgrmetalhspgrwood=0
h= (.1 spgrmetal)/(1+sprgwood)= about .5/(1.5)=33cm ?
check my work.
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