algebra
posted by Lost .
How do I solve for x on both sides of the equation, i.e. 72x+48=42x12? Is there a standard way of figuring this out?

72x+48=42x12
First, subtract 42x from both sides.
72x  42x + 48 = 42x  42x  12
30x + 48 = 12
Then subtract 48 from both sides.
30x = 48 + (12)
30x = 60
x = 60/30
x = 2
Respond to this Question
Similar Questions

Algebra
Solve each literal equations for the indicated variable D = C  s/n ( for s) s/n = D  C Next, multiply both sides of the above equation by n, to get the equation for s. i don't understand could you type it how it looks This is an … 
can someone help me with a question of an explanat
my question is for math, I have the problem worked out i just don't remember what the tutor who helped me told me for the explanation of steps i just like to know how they came up with that. Directions: Solve each literal equation … 
MATH PLEASE CHECK IT!!2
m2/m5*m+5/m2=1 If your problem is this: (m  2)/(m  5) * (m + 5)/(m  2) = 1 (m  2) cancels out in both the numerator and denominator on the lefthand side since you are multiplying. That leaves us with this: (m + 5)/(m  5) … 
math
I need help figuring out these two questions on euations with integers. 5x+20=60 2x3=2 thank you so much for first: subtract 20 from both sides, simplify, then divide both sides by 5 for second: add 3 to both sides, simplify, … 
Maths
you have to solve the following by finding the value of x and y. can u help please? 
Algebra
Solve Q= (NS)/ N for N So when I multiply both sides by N I get Q(N)= NS I know I am doing something wrong, the answer is in the book which is N=S/(1Q)but I don't understand were the 1 comes from. Could you write it out step by … 
AlgebraCorrection?
Solve the absolute value equation. I I will represent absolute value I 2x4 I 1= 11 Would the solutions be x=8 and x= 4? 
Precalc Solve logarithmic
ln sqrt(x8)= 5 I would like help to solve this what i did was to take away the square root i squared both sides coming up with (ln sqrt(x8))^2= (5)^2 ln(x8)=25 am i alowed to do this with ln in the equation? 
algebra solving log equations
n sqrt(x8)= 5 I would like help to solve this what i did was to take away the square root i squared both sides coming up with (ln sqrt(x8))^2= (5)^2 ln(x8)=25 am i alowed to do this with ln in the equation? 
algebra
1 2 1+x = 72x 1 2 1/1+1/x =1/72x 2 1 2 2 (72x /1)1/1+1/x =1/72x (72x/1) 2 72x +72x=1 got stuck here